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Yeah, I don't want to be spamming the Math is Cool thread so I thought that I should make this.


Well, ya I need some help with my math homework. ASAP would be helpful...<snip> I just need help

Solve by using elimination:


10 x+6y+13






I would greatly appretiate any help...

Edited by Rev7
sorry, Im tired
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-6 -6



Final Answer:




This is on my homework, and I have no one to help me. I have attemped them, but am a little stuck and need some help. That is all.

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10 x+6y+13


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(-3) 8x+3y+5=0










10 x+6y+13=0





This is where I am stuck.


If you "mainly just forgot" then just check that section in your text book.

It is on a worksheet. :)



I see my mistake in that...fixed...still stuck though

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Math only taught me one thing. If the guy is using letters instead of numbers to work out the bill, punch him in the face.

They're know as Pro-numerals, punching him in the face seems like the logical thing to do :p


I'm trying to figure out the answers Rev7, but I'm a bit stuck as to the answer in the second line of the first question, I do believe there's supposed to be an answer there, or am I missing something?

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And you said you would have the skills to help me if I needed help, lol.


Your math looks slightly more advanced than what I'm at at the moment. My Algebra class is doing those same kinds of equations, and tommorw is when I bet we'll be using fractions...


Although I think I understand this already...


My advice: Eliminate the smallest variable term first.




7n-2=5n + 6

-5n -5n

2n - 2 = 6

+ 2 + 2

2n = 8

/2 /2

n = 4



In this, the variable is n. one side had 7n, one side has 5n. You get rid of the lesser variable first. I got rid of 5n first. As for negative variables and positive variables - get rid of the negative variable first. (or the negative variable farthest from 0) Think of integers. Anything less than 0 is smaller than anything more than 0...




for -5n and -7n, -7n is the smaller variable term.

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What we are doing is solving systems of equations Algebraically.


Eventually we will make graphs with them. This is a review for me, it is just it has been a good year before I last did something like this and I got stuck. Today's homework is/was on the hard side.


@Arc--what you were doing is correct, my equations are just a little bit more....advanced/harder/have more steps...I understand what you are doing. :)

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Solve for 3y and then substitute in the second line:


8x + 3y + 5 = 0


10x + 6y + 13 = 0


=> first line = 3y = -8x - 5 So Second line equals,


10x + 2(-8x - 5) + 13 = 0


10x + -16x - 10 + 13 = 0


-6x + 3 = 0


-6x = -3


6x = 3


x = .5





4 + 3y + 5 = 0


3y = -9


y = -3




10(.5) + 6(-3) + 13 = 0


5 + -18 + 13 = 0


=> True

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If I remember this type of equation correctly, as tk mentioned, you 'line up' the equations, eliminate one of the two variables, and go to town.







Now, since none of the variables are equal, we need to make 'em equal. So, let's try to get the "x" variables equal.



(NOTE: in order to get the "x"s equal, we need to multiply this equation by -5. -5, so that the two will cancel out [-5+5=0]Therefore...) x(-5)+3(-5)y=-7.5(-5)


Now simplified:




"X"s cancel out...





Now, if I did that correctly, "y" should equal 2.5 Go back into the equation, plug "y" in, and you should be able to solve the one-variable equation.


I hope that helps.

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