Cmdr. Cracken Posted May 16, 2002 Author Posted May 16, 2002 um... i don't know, let me check. 81*F=27*C
guildenstern Posted May 16, 2002 Posted May 16, 2002 Yay! Then I was so very right when I guessed "80 degrees or slightly over" Woohoo! Thanks, Q.
Cmdr. Cracken Posted May 17, 2002 Author Posted May 17, 2002 ZIM! I SEE ZIM IN THAT AVATAR! ZIM RULES! Gir:I loveded you piggy.... why piggy, WHYYY!!?!??!?!?!
Taarkin Posted May 17, 2002 Posted May 17, 2002 I certainly hope Nine is more loyal with his women than he is with his avatars. On second thought, I don't. More for me.
Keyan Farlander Posted May 17, 2002 Posted May 17, 2002 Originally posted by guildenstern Yay! Then I was so very right when I guessed "80 degrees or slightly over" Woohoo! Thanks, Q. Wait, wait, wait - I posted those beautiful conversion formulas just for you, little guildenstern, and you didn't use them!? I feel so unloved
guildenstern Posted May 17, 2002 Posted May 17, 2002 Well the truth is (*ashamed*) they looked a little froody to me and I thought you were just being facesious... it was the whole (9/5) / (5/9) thing that threw me! I didn't see those fractions as having any place in those formulas! And I still don't!! I'm sorry O_O Except now I see that that probably means "divided by" and so I feel even more dork-assier. Ah well. me not smrt to nokw the convershuns. But now I know for next time. ^_^
Keyan Farlander Posted May 17, 2002 Posted May 17, 2002 *SNIFF* Well, okay... But they are for real. It does make sense because there should be a scaling factor (the fraction) and an offset (the 32). Try it with what you know - boiling and freezing. Boiling point in F is 212 and in C is 100. Remember the formulas: To convert Celcius to Fahrenheit: F = C * (9/5) + 32 To convert Fahrenheit to Celcius: C = (F - 32) * (5/9) So, let's do boiling, C to F. F=100*(9/5)+32 = 100*1.8+32 = 180+32 = 212 OK, it works. Now backwards just for good measure. C=(212-32)*(5/9) = 180*(5/9) = 180/1.8 = 100 OK, that works too. For freezing (32 F and 0 C), C to F. F = 0*(9/5)+32 = 0+32 = 32 OK. For F to C C = (32-32)*(5/9) = 0*(5/9) = 0 OK. So, there's some intuition that it works from checking those examples. Now for your specific tempuratre, 27 C. F = 27*(9/5)+32 = 27*1.8+32 = 48.6+32 = 80.6 So, that's what it is. See, I wouldn't lie to you! Now keep those formulas handy!
guildenstern Posted May 17, 2002 Posted May 17, 2002 I shall. ^_^ And thank you for that little algebra lesson. Really! I quite enjoyed it. Feel free to give me more. Laterz!
KNIGHT_FEDAYKIN Posted May 17, 2002 Posted May 17, 2002 Originally posted by guildenstern I shall. ^_^ And thank you for that little algebra lesson. Really! I quite enjoyed it. Feel free to give me more. Laterz! Return of the Maths Thread ?
Rogue Nine Posted May 17, 2002 Posted May 17, 2002 Ssssssshhhhh!!! *smacks FEDDY* Don't give Keyan any ideas.
KNIGHT_FEDAYKIN Posted May 17, 2002 Posted May 17, 2002 some mean person closed the original *glares*
Keyan Farlander Posted May 18, 2002 Posted May 18, 2002 Hmm, actually... I had been thinking about doing a thread about how some various parts of a computer work, for those interested but who have not have the opportunity to learn yet. Maybe something like that.
KNIGHT_FEDAYKIN Posted May 18, 2002 Posted May 18, 2002 Originally posted by Keyan Farlander Computers ARE math. maths.
Keyan Farlander Posted May 18, 2002 Posted May 18, 2002 Originally posted by KNIGHT_FEDAYKIN maths. Math. ;)
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