Beer Matamatics

[Natty]

BEER MATHEMATICS

This is pretty neat how it works out.

 

This is amazing beer math!!!!!!!

 

1. First of all, pick the number of times a week that you would like to have a beer (try for more than once but less than

10; if your answer is zero, substitute your favourite drink/treat)

 

2. Multiply this number by 2 (Just to be bold)

 

3. Add 5. (for Friday Night)

 

4. Multiply it by 50 (being a bit stupid)

 

5. If you have already had your birthday this year add 1751.... If

you haven't, add 1750 ..........

 

6. Now subtract the four digit year that you were born. (if you remember)

 

You should have a three digit number

 

The first digit of this was your original number (I.e., how many times you want to have a beer each week).

 

The next two numbers are your age.

 

------------------

[Guest The Feral Chicken]

How odd...

[NiKo]

i'm 73?

[MagnusB]

Hmm, I always wonder how these things work.....

[NiKo]

i'm 73!?!

 

[Guest grannen]

Originally posted by MagnusB:

Hmm, I always wonder how these things work.....

 

There is a very simple calculation/explanation!

Do the same but instead of the number of beers replace it with the number of people living at your home (but it has to be less than 10!)

 

Or your cat/dog/birds age (but still less than 10)

 

So, who of you can tell us how it mathematicaly (is there any such word?) works?

I can do it but this is a nice problem for you now when the school has started.

 

------------------

and Grannen

[Drunken_Sailor]

Originally posted by Natty:

BEER MATHEMATICS

This is pretty neat how it works out.

 

This is amazing beer math!!!!!!!

 

1. First of all, pick the number of times a week that you would like to have a beer (try for more than once but less than

10; if your answer is zero, substitute your favourite drink/treat)

 

2. Multiply this number by 2 (Just to be bold)

 

3. Add 5. (for Friday Night)

 

4. Multiply it by 50 (being a bit stupid)

 

5. If you have already had your birthday this year add 1751.... If

you haven't, add 1750 ..........

 

6. Now subtract the four digit year that you were born. (if you remember)

 

You should have a three digit number

 

The first digit of this was your original number (I.e., how many times you want to have a beer each week).

 

The next two numbers are your age.

 

 

Of all your ideas,this has to be the funniest

[Guest grannen]

Originally posted by NiKo:

i'm 73!?!

 

Math is not your best subject at school, old man?

 

------------------

and Grannen

 

 

 

[This message has been edited by Grannen (edited September 01, 2001).]

[NiKo]

Originally posted by Grannen:

Math is not your best subject at school, old man?

 

lets just put it this way, "1+1=5"

 

 

[raVen_image]

Originally posted by Grannen:

Math is not your best subject at school, old man?

 

 

Or if you Are an old man. This little mathematical-ditty only works within a certain age group. Outside those parameters, and it fails

 

[Guest grannen]

Originally posted by raVen_image:

Or if you Are an old man. This little mathematical-ditty only works within a certain age group. Outside those parameters, and it fails

 

It works if you multiply with 20 instead of 2. (Unless you are 1000 years old, or more.)

The first digit is still the number of beers and the last three digits is your age.

 

------------------

and Grannen

 

[This message has been edited by Grannen (edited September 01, 2001).]