greedo626 Posted November 4, 2004 Posted November 4, 2004 See if you can figure these out. Question 1: In the following addition problem, the letters A, B, and C stand for three different digits. What digit should replace each letter? ABC + ACB =CBA Question 2: In the following subtraction problem, the letters A, B, and C stand for three different digits. What digit should replace each letter? ABA - CA = AB :confused:
Shok_Tinoktin Posted November 4, 2004 Posted November 4, 2004 Answer 1: A=4, B=5, and C=9 Answer 2: A=1, B=0, and C=9
matt-- Posted November 4, 2004 Posted November 4, 2004 100A + 10B + C + 100A + 10C + B = 100C + 10B + A 200A + 11B + 11C = 100C + 10B + A 199A + B = 89C A=4, C=9 199(4) + B = 89(9) 796 + B = 801 B=5 ABC + ACB = CBA 459 + 495 = 954 Solution 2 will wait until later.
Rogue15 Posted November 5, 2004 Posted November 5, 2004 I can't [under]stand that kind of math. I'm not even gonna try.
Sabretooth Posted November 5, 2004 Posted November 5, 2004 *blink blink* Good Title, "Revenge of the Brain Teaser" parallel to "Revenge of the Sith Teaser" where the "Sith Teaser" is one of Astro's Scandinavian Nymphos. What? Ah yes, I'm with Shok Tinoktin on this. He beat me to it. <_< >_> >_<
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