Hallucination Posted April 14, 2007 Posted April 14, 2007 ^Inspires fear with a depiction of a man whose sword is bigger than he.
Ctrl Alt Del Posted April 15, 2007 Posted April 15, 2007 ^Wants to impress one, but fails completely, thanks to the pinky monocle.
Diego Varen Posted April 15, 2007 Author Posted April 15, 2007 ^ Something off Soul Calibur, which is made by Namco, the same makers of the Tekken series.
Hallucination Posted April 15, 2007 Posted April 15, 2007 ^Talks of evil Sith, opposed to the Sith that give people cookies and hugs.
St. Jimmy Posted April 15, 2007 Posted April 15, 2007 ^ Sig reminds me of the warning on the rocket launcher in HALO.
Ctrl Alt Del Posted April 16, 2007 Posted April 16, 2007 ^Statement above is incorrect. It says: "Self-test", on the rocket launcher.
CSI Posted April 16, 2007 Posted April 16, 2007 ^The heavier sword, the slower the blow. Keep that in mind.
St. Jimmy Posted April 17, 2007 Posted April 17, 2007 ^Statement above is incorrect. It says: "Self-test", on the rocket launcher. Nu uh.. How could my statement be wrong if it's subjective? Also, I'm pretty sure it doesn't just say Self test...... But you may be right..
Det. Bart Lasiter Posted April 17, 2007 Posted April 17, 2007 ^The heavier sword, the slower the blow. Keep that in mind. Not if you're swinging it downwards.
Ray Jones Posted April 17, 2007 Posted April 17, 2007 Yeah, also, if you hit with the same velocity the heavier sword will cut deeper or more easily through the enemy's armour due to higher mass inertia.
Jae Onasi Posted April 17, 2007 Posted April 17, 2007 Having actually used real (not just the euphemistic one, Ray ) swords of varying sizes, I can tell you from experience that bigger swords have more mass, and thus they really are slower. It takes a lot more force to move a great sword at the same speed as a foil, for instance, even if you're swinging down (you typically move the sword faster than gravity can). The advantage the longer sword has is that if you hit someone somewhere around the end of the sword it does more damage because a longer sword creates more torque. It takes longer to move a bigger sword, but the extra mass and length allow it to do more damage when you do hit. Your sword-fighting lesson du jour. @Ray below--I was thinking more along the lines of jmac's and CSI's post than yours. F=ma (Force=mass*acceleration), so you increase the mass, you increase the Force. You don't want to make the sword too wide though, or it gets too unwieldy to use, plus you lose the torque advantage (T=Fd, or torque=force*distance from center). So if you have the same force applied, the torque is twice as high when you get twice as far from center (fulcrum). In our non-choreographed 'fighting' we use fake swords (made out of rattan). The fighters aren't allowed to bring the 2-handed swords behind their head--the maximum arc that the sword can move is 90 degrees because if that big of a sword gets moving too fast, it can cause some pretty big injuries if you get hit by the very end of the sword.
Ray Jones Posted April 17, 2007 Posted April 17, 2007 I said *same* velocity. E=mc². Higher m with same c means higher E means higher *slash*. Oh, and heavier mustn't mean longer, it can be broader and shorter, for instance, that means you need less or same torque to handle it. Still you'll need more strength to lift and hold it up. But that is why you should always drink your milk! ;
CSI Posted April 18, 2007 Posted April 18, 2007 ^Has a very classic photo in his signature. I said *same* velocity. E=mc². Higher m with same c means higher E means higher *slash*. Oh, and heavier mustn't mean longer, it can be broader and shorter, for instance, that means you need less or same torque to handle it. Still you'll need more strength to lift and hold it up. But that is why you should always drink your milk! ; Ray Jones, no offense meant, if you don't know what that formula means check before you speak...E=Energy, M=Mass, but C? C=Velocity of Light in vaccum... I don't think anyone can wave the sword in light speed, can he/she/it? I think that formula should be: K.E.=1/2mv², where KE=Kinetic Energy, M=Mass, V=Velocity. And I think the second statement is also wrong: Because t=rF, which t=Torque, r=Radius Vector, and F=Force exerted, which means, under the same Force, the longer the sword is, the bigger the torque is...The width of the sword has nothing to do with the torque... Therefore, if Force is up, but the radius vector is down [because of the scenerio=Heavy but short sword], it doesn't necenssarily represent bigger torque... I might be wrong, and I'm happy that someone would correct me. Thank you.
Ray Jones Posted April 18, 2007 Posted April 18, 2007 Right it should be v substituted for c, but why not swinging the sword with c? But still, the explanation and principle of what I said stands, and I think I fully understand what that formula means, 'coz I'm really deep into physics and maths. And I also said that a heavier sword must not be longer, it can be shorter and still be heavier, when it's broader or made of different steel/material, one with higher density. The width of a sword is relevant to torque too, as is has an influence on the mass, which again correlates to torque.
Jae Onasi Posted April 18, 2007 Posted April 18, 2007 ^ Blond guy needs more practice in defending against knife attacks. If you have equal mass, a long, thin sword exert the same amount of force as a short, wide sword. However, the amount of torque created at the end of the longer sword is greater than the shorter one, since the tip of the longer sword is farther away from center.
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